Other posts from this series:
DataWeave programming challenge #1: Add numbers separated by paragraphs and get the max number
DataWeave programming challenge #2: Rock Paper Scissors game score system
DataWeave programming challenge #3: Count palindrome phrases using the Strings module
DataWeave programming challenge #4: Solve the Tower of Hanoi mathematical puzzle
DataWeave programming challenge #5: Reverse a phrase's words, but keep the punctuation
DataWeave programming challenge #6: Using tail-recursion to get the factorial of a number
DataWeave programming challenge #7: Modify certain values from a JSON structure
DataWeave programming challenge #8: Sum all digits to get a 1-digit number
In this post:
Try to solve this challenge on your own to maximize learning. We recommend you refer to the DataWeave documentation only. Try to avoid using Google or asking others so you can learn on your own and become a DataWeave expert!
Input
Consider the following input payload (can be of txt format):
3
5
-6
300
Explanation of the problem
Create a tail-recursive function to get the factorial of each positive number from the payload.
Sum the results.
Retrieve the digits/characters located at positions 20-25.
Make sure to return a number and not a string.
Numbers 0 or less won't be calculated.
For example:
The factorial of 3 is 6 (3 x 2 x 1)
The factorial of 5 is 120 (5 x 4 x 3 x 2 x 1)
The factorial of -6 won't be calculated so the result will be 0
And so on
Once the results are summed (6 + 120 + 0...), extract the digits at indexes 20 to 25.
Return this last 6-digit number.
Expected output
In this case, the expected output would be:
537046
Clues
If you're stuck with your solution, feel free to check out some of these clues to give you ideas on how to solve it!
Answer
If you haven't solved this challenge yet, we encourage you to keep trying! It's ok if it's taking longer than you thought. We all have to start somewhere ✨ Check out the clues and read the docs before giving up. You got this!! 💙
There are many ways to solve this challenge, but you can find here one of my solutions!
Solution #1
Feel free to comment your code below for others to see! 😄
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For those using dw::core::Arrays slice it excludes the last index, so select 20-26
%dw 2.0 output application/json fun solve(x)= x reduce(item, acc) -> ( (if(item > 0) acc + factorial(item) else acc)) fun factorial(x)= 2 to x reduce(item, acc) -> (acc*item) --- (solve(payload splitBy('\n')) splitBy(''))[20 to 25] joinBy('')
%dw 2.0 fun factorial(num)= num to 1 reduce ((item, accumulator) -> accumulator * item) fun pos(val) = val[20 to 25] --- pos(sum((payload splitBy "\n" ) map factorial($))) as Number
Tried this out. :)
https://gist.github.com/Shadow-Devil/38922025e3ab95f18bc21633eae5f27f